Bourbaki

Exercise 17, § 3

Commutative Algebra, III, 250

Bourbaki marks this one as harder than the rest.

(a) Let KK be a commutative field, A=K[[X1,…,Xn]]A = K[[X_1, \ldots, X_n]] the ring of formal power series in nn indeterminates with coefficients in KK and VV a vector space over KK. With the notation of § 2, no. 6, Example 1, let V[[X1,…,Xn]]V[[X_1, \ldots, X_n]] denote the vector space VnnV^{n^n} with the AA-module structure defined by

(∑αcαXα)(vα)=(wα), \left( \sum_\alpha c_\alpha X^\alpha \right)(v_\alpha) = (w_\alpha),

where wα=∑β+γ=αcβvγw_\alpha = \sum_{\beta + \gamma = \alpha} c_\beta v_\gamma. Show that, if VV admits a basis with II as indexing set, the AA-module V[[X1,…,Xn]]V[[X_1, \ldots, X_n]] is isomorphic to A′A' if II is finite and to the AA-module AA, defined in Exercise 16 if II is infinite. Deduce that V[[X1,…,Xn]]V[[X_1, \ldots, X_n]] is a flat AA-module and is faithfully flat if VV is not reduced to 0.

(b) Let LL be an extension of the field KK. Deduce from (a) that the ring of formal power series L[[X1,…,Xn]]L[[X_1, \ldots, X_n]] is a faithfully flat module over the ring K[[X1,…,Xn]]K[[X_1, \ldots, X_n]]. If LL has finite rank over KK, L[[X1,…,Xn]]L[[X_1, \ldots, X_n]] is isomorphic to L⊗KK[[X1,…,Xn]]L \otimes_K K[[X_1, \ldots, X_n]].

(c) If LL is an algebraic extension of KK, show that the ring L[[X1,…,Xn]]L[[X_1, \ldots, X_n]] is a faithfully flat module over the ring

L⊗KK[[X1,…,Xn]] L \otimes_K K[[X_1, \ldots, X_n]]

(consider LL as the direct limit of its sub-extensions of finite rank over KK and use Chapter I, § 2, no. 7, Proposition 9). Deduce that the ring

B=L⊗KK[[X1,…,Xn]] B = L \otimes_K K[[X_1, \ldots, X_n]]

is a Noetherian local ring whose completion is identified with L[[X1,…,Xn]]L[[X_1, \ldots, X_n]]. In order that B^=B\hat{B} = B, it is necessary and sufficient that n=0n = 0 or [L:K]<+∞[L : K] < +\infty.

Solution

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Transcribed from the printed volume. Not translated.