Exercise 16, § 2
Commutative Algebra, V, 366
Let be an integral domain, its field of fractions, a finite extension of of degree and a subring of containing , with as field of fractions and integral over . Let be a maximal ideal of and the local ring (Exercise 15).
(a) The subring of is integral over ; its field of fractions is and .
(b) For every maximal ideal of containing , is a maximal ideal of ; if we write , then
and
(Observe that is isomorphic to the field and deduce that is isomorphic to .)
(c) The mapping is the bijection of the set of maximal ideals of containing onto the set of maximal ideals of ; the inverse bijection is .
Solution
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