Bourbaki

Exercise 18, § 2

Commutative Algebra, V, 367

Bourbaki marks this one as harder than the rest.

Let AA be a local integrally closed domain, KK its field of fractions, mm its maximal ideal and k=A/mk = A/m its residue field. Let K′K' be a finite algebraic extension of KK of degree nn, A′A' a subring of KK containing AA, integral over AA and with K′K' as field of fractions and mim_i (1≤i≤r1 \leq i \leq r) the maximal ideals of AA. An ideal mm is called unramified in A′A' if there exists a basis (wi)1≤i≤r(w_i)_{1 \leq i \leq r} of K′K' over KK consisting of elements of A′A' and whose discriminant DK′/K(w1,…,wr)D_{K'/K}(w_1, \ldots, w_r) (Algebra, Chapter IX, § 2) belongs to A−mA - m.

(a) Show that, if mm is unramified in A′A', K′K' is a separable extension of KK, A′A' is the integral closure of AA in K′K' and is a free AA-module every basis of which over AA is a basis of K′K' over KK; mA′mA' is the Jacobson radical of A′A' and A′/mA′A'/mA' is a semi-simple kk-algebra of rank nn over kk which is separable over kk and the direct composition of the fields A′/mi′A'/m_i'.

(b) Let did_i be the separable factor of the degree of A′/mi′A'/m_i' over A/mA/m. Show that, if kk is infinite, ∑idi≤n\sum_i d_i \leq n (use Exercise 17 (c)); moreover, the following conditions are equivalent: (α) mm is unramified in A′A'. (β) A′A' is a finitely generated AA-module and A′/mA′A'/mA' is a semi-simple kk-algebra and separable over kk. (γ) ∑i=1rdi≤n\sum_{i=1}^r d_i \leq n. (To see that (β) implies (γ), note that there is a system of generators of the AA-module A′A' whose classes mod. mA′mA' form a basis of A′/mA′A'/mA' over kk, using Chapter II, § 3, no. 2, Corollary 2 to Proposition 4; deduce that

[K′:K]≤[(A′/mA′):k]. [K': K] \leq [(A'/mA') : k].
To see that (γ) implies (α), use Exercise 17 (c) to show that there exists a basis of A′/mA′A'/mA' over kk consisting of the powers ξi\xi^i of an element ξ\xi (0≤i≤n−10 \leq i \leq n-1); if x∈A′x \in A' is an element of the class ξ\xi, deduce that DK′/K(1,x,…,xn−1)D_{K'/K}(1, x, \ldots, x^{n-1}) belongs to A−mA - m.) Give an example where K′K' is separable over KK, A′/mA′=A/mA'/mA' = A/m and A′A' is not a finitely generated AA-module (cf. Exercise 9 (c)).

(c) Extend the results of (b) to the case where kk is finite (in the notation of Exercise 16, show that, if nn is unramified in B′B', then mm is unramified in A′A'; taking account of the fact that B/nB/n is infinite, use Exercise 16 (c), thus obtaining an element t∈B′t \in B' such that

DK′(x)/K(x)(1,z,…,zn−1)∈B−n; D_{K'(x)/K(x)}(1, z, \ldots, z^{n-1}) \in B - n;
show that zz may be assumed to be a polynomial in A′[X]A'[X] and, by expressing the above discriminant as a polynomial in XX, obtain the existence of a system of nn elements wiw_i (1≤i≤n1 \leq i \leq n) of A′A' such that DK′/K(w1,…,wr)∈A−mD_{K'/K}(w_1, \ldots, w_r) \in A - m).

Solution

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