Exercise 8, § 1
Commutative Algebra, VI, 443
Bourbaki marks this one as harder than the rest.
Given a ring , a polynomial with coefficients in is called dominated if it is of the form , where in the product ordered set for all such that . In a ring , a subring is called paravaluative if, for every dominated polynomial (any ), for all elements ().
(a) Show that, if is paravaluative in , the product of two elements of belongs to .
(b) Let be a subring of a ring such that the product of two elements of belongs to ; let be the prime ideal of and consisting of the such that for all (Exercise 6 (b)). For to be paravaluative in , it is necessary and sufficient that be paravaluative in .
(c) Let be a ring and a ring homomorphism. If is a paravaluative subring of , is paravaluative in . Deduce that, if is a maximal ordered pair in (Exercise 7), is paravaluative in (use (b) and Exercise 7 (d) and (e)).
(d) Let be a ring and a subring of . If is a paravaluative subring of , show that there exists a paravaluative subring of such that . (If and , consider the ring and the canonical homomorphism . Let be the subring of generated by and the ideal of generated by . Show that ; consider a maximal ordered pair in such that and and take .)
Conclude from this that, if is an integral domain, the paravaluative subrings of are the intersections of with the valuation rings of the field of fractions of .
Solution
No solution has been written yet.