Exercise 1, § 4
Commutative Algebra, VI, 449
(a) Let G be a totally ordered group and M a major set in G, not containing 0. Show that there exists a greatest isolated subgroup H of G not meeting M.
(b) Let A be a valuation ring and a valuation associated with A. For an ideal of A to be prime, it is necessary and sufficient that p correspond to a major set M in the totally ordered value group G of such that, if H is the greatest isolated subgroup of G not meeting M, M is the complement of in G,.
(c) With the notation of (b), for an ideal q of A to be p-primary, it is necessary and sufficient that it satisfy one of the following conditions: either (and p is then maximal) or .
(d) For an ideal a of A which is distinct from 0 and A to satisfy , it is necessary and sufficient that a correspond to a major set M such that, if H is the greatest isolated subgroup of G not meeting M, the image of M in the totally ordered group has no least element; a is then a prime ideal.
Solution
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