Bourbaki

Exercise 6, § 4

Commutative Algebra, VI, 450

Bourbaki marks this one as harder than the rest.

(a) Let SS be a hyperstonian compact space with no isolated point (Integration, Chapter V, §5, Exercise 14). Let C0(S)C_0(S) be the vector space of realvalued functions, finite or otherwise, defined on S, continuous on S and such that the sets f(−∞)f(-\infty) and f(+∞)f(+\infty) are nowhere dense in S (Integration, Chapter II, § 1, Exercise 13 (g)). Show that, for every measure μ>0\mu > 0 on S, there exist functions ff in C0(S)C_0(S) whose upper integral is infinite (note that for every nowhere dense closed subset N of S there exists a function ff in C0(S)C_0(S) which is equal to +∞+\infty on N; show then that attention may be restricted to the case where the measure μ\mu is normal and define ff suitably as the upper bound of a sequence of functions in C0(S)C_0(S)).

(b) Let G be the ordered subgroup of C0(S)C_0(S) consisting of the functions in C0(S)C_0(S) whose values in Z\mathbf{Z} or ±∞\pm \infty. Show that G is a complete lattice and is not isomorphic (as an ordered group) to any subgroup of a product group Rl\mathbf{R}^l.

(c) Let K be a field and As=K[[Xs]]s∈SA_s = K[[X_s]]_{s \in S} the ring of formal power series with coefficients in K in a family of indeterminates (Xs)(X_s) with the space S as indexing set (Algebra, Chapter IV, § 5, Exercise 1). Let b be the set of formal power series P∈AsP \in A_s with the following property: there exists a nowhere dense set N⊂SN \subset S such that every monomial of P whose coefficient is ≠0\neq 0 contains an XsX_s for which s∈Ns \in N. Show that b is an ideal of A0A_0 and that the ring A=A0/bA = A_0/b is an integral domain and completely integrally closed (to prove the latter point, apply Chapter V, § 1, no. 4, Proposition 14, arguing as in Chapter V, § 1, Exercise 10; use also the fact that in S every meagre set is nowhere dense).

(d) Let ff be an element ≥0\geq 0 of the group G and let N be the nowhere dense set of points where f(s)=±∞f(s) = \pm \infty. Let pfp_f be the element of A the image of the formal power series ∏s∈N(1+Xs)f(s)\prod_{s \in N} (1 + X_s)^{f(s)}; the mapping f↦pff \mapsto p_f is an isomorphism of the additive monoid G+G_+ onto a multiplicative submonoid of A. Deduce that A cannot be the intersection of a family of valuation rings of height 1 of its field of fractions (show that this would imply that G is isomorphic to a subgroup of a product Rl\mathbf{R}^l). (Cf. Exercises 8 and 9.)

Solution

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