Exercise 6, § 4
Commutative Algebra, VI, 450
Bourbaki marks this one as harder than the rest.
(a) Let be a hyperstonian compact space with no isolated point (Integration, Chapter V, §5, Exercise 14). Let be the vector space of realvalued functions, finite or otherwise, defined on S, continuous on S and such that the sets and are nowhere dense in S (Integration, Chapter II, § 1, Exercise 13 (g)). Show that, for every measure on S, there exist functions in whose upper integral is infinite (note that for every nowhere dense closed subset N of S there exists a function in which is equal to on N; show then that attention may be restricted to the case where the measure is normal and define suitably as the upper bound of a sequence of functions in ).
(b) Let G be the ordered subgroup of consisting of the functions in whose values in or . Show that G is a complete lattice and is not isomorphic (as an ordered group) to any subgroup of a product group .
(c) Let K be a field and the ring of formal power series with coefficients in K in a family of indeterminates with the space S as indexing set (Algebra, Chapter IV, § 5, Exercise 1). Let b be the set of formal power series with the following property: there exists a nowhere dense set such that every monomial of P whose coefficient is contains an for which . Show that b is an ideal of and that the ring is an integral domain and completely integrally closed (to prove the latter point, apply Chapter V, § 1, no. 4, Proposition 14, arguing as in Chapter V, § 1, Exercise 10; use also the fact that in S every meagre set is nowhere dense).
(d) Let be an element of the group G and let N be the nowhere dense set of points where . Let be the element of A the image of the formal power series ; the mapping is an isomorphism of the additive monoid onto a multiplicative submonoid of A. Deduce that A cannot be the intersection of a family of valuation rings of height 1 of its field of fractions (show that this would imply that G is isomorphic to a subgroup of a product ). (Cf. Exercises 8 and 9.)
Solution
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