Bourbaki

Exercise 9, § 4

Commutative Algebra, VI, 452

Bourbaki marks this one as harder than the rest.

Let AA be a Laskerian completely integrally closed domain (Chapter IV, § 2, Exercise 23). Suppose further, that, for all x≠0x \neq 0 in AA, the prime ideals pip_i,

(*) There exist examples of local integral domains of dimension 1 which are completely integrally closed but are not valuation rings (cf. P. Ribenboim, Sur une note de Nagata relative à un probléme de Krull, Math. Zeitsch., v. LXIV (1956), pp. 159–168).

weakly associated with A/AxA/A_x (Chapter IV, § 1, Exercise 17) are all of height 1, that is to say that for all ii, pip_i contains no prime ideal other than itself and 0 (cf. Chapter VII, § 1, no. 6). Show that under these conditions AA is an intersection of valuation rings of height 1. (Show first that AA is the intersection of all the rings ApA_p, where pp runs the set of prime ideals of height 1, using Exercise 17 (i) of Chapter IV, § 1. Then prove that these local rings ApA_p are completely integrally closed, using condition (LA1_1) of Chapter IV, § 2, Exercise 23. Finally apply Exercise 8.) The above hypotheses are in particular satisfied when AA is a Laskerian completely integrally closed domain in which every ideal admits a single primary decomposition (Chapter IV, § 2, Exercise 26).

Solution

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