Exercise 9, § 4
Commutative Algebra, VI, 452
Bourbaki marks this one as harder than the rest.
Let be a Laskerian completely integrally closed domain (Chapter IV, § 2, Exercise 23). Suppose further, that, for all in , the prime ideals ,
(*) There exist examples of local integral domains of dimension 1 which are completely integrally closed but are not valuation rings (cf. P. Ribenboim, Sur une note de Nagata relative à un probléme de Krull, Math. Zeitsch., v. LXIV (1956), pp. 159–168).
weakly associated with (Chapter IV, § 1, Exercise 17) are all of height 1, that is to say that for all , contains no prime ideal other than itself and 0 (cf. Chapter VII, § 1, no. 6). Show that under these conditions is an intersection of valuation rings of height 1. (Show first that is the intersection of all the rings , where runs the set of prime ideals of height 1, using Exercise 17 (i) of Chapter IV, § 1. Then prove that these local rings are completely integrally closed, using condition (LA) of Chapter IV, § 2, Exercise 23. Finally apply Exercise 8.) The above hypotheses are in particular satisfied when is a Laskerian completely integrally closed domain in which every ideal admits a single primary decomposition (Chapter IV, § 2, Exercise 26).
Solution
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