Bourbaki

Exercise 9, § 5

Commutative Algebra, VI, 457

Bourbaki marks this one as harder than the rest.

Let AA be a discrete valuation ring, π\pi a uniformizer of AA and KK the field of fractions of AA; suppose that AA is complete with the π\pi-adic topology. The injective AA-modules (Algebra, Chapter II, § 2, Exercise 11) are identical with the divisible AA-modules (Algebra, Chapter VII, § 2, Exercise 3) and are direct sums of AA-modules isomorphic either to KK or to K/AK/A (Algebra, Chapter VII, § 2, Exercise 3). Moreover, every monogenous AA-module is isomorphic to a submodule of K/AK/A. The AA-module HomA(M,K/A)\mathrm{Hom}_A(M, K/A) is called the (algebraic) toric dual of an AA-module MM and denoted by M∗M^*; the canonical mapping cM:M→M∗∗c_M : M \to M^{**} is injective (Algebra, Chapter II, § 2, Exercise 13 (b)). For every submodule NN of MM the submodule N0N^0 of M∗M^* consisting of the uu such that u(x)=0u(x) = 0 is called the orthogonal of NN in M∗M^*; the dual of M/NM/N is canonically identified with N0N^0 and the dual of NN with M∗/N0M^*/N^0. The toric dual of a direct limit lim←⁡Mα\varprojlim M_\alpha is canonically isomorphic to the inverse limit lim←⁡Mα∗\varprojlim M_\alpha^*.

(a) We know that the AA-modules of rank one (Algebra, Chapter VII, § 4,

Exercise 22) are isomorphic to a module of one of the form A, K, K/A or A/πnAA/\pi^n A. Show that the algebraic toric duals of K and A/πnAA/\pi^n A are respectively isomorphic to K and A/πnAA/\pi^n A, that the toric dual of A is isomorphic to K/A and that that of K/A is isomorphic to A (use the knowledge about the sub-A-modules of K and the fact that A is complete (with respect to the dual of K/A)). Deduce that, for every A-module M of finite rank, M∗M^* is a module of the same rank and that the canonical homomorphism cMc_M is bijective.

(b) Let M be an A-module and N a submodule of M of finite rank. Show that the orthogonal of N0N^0 in M∗∗M^{**} is identified (by cMc_M) with N (use (a)).

(c) Show that an A-module M which is Noetherian (resp. Artinian) is of finite rank (embed M in its injective envelope (Algebra, Chapter II, § 2, Exercise 18)); then M∗M^* is Artinian (resp. Noetherian).

(d) Let σ(M∗,M)\sigma(M^*, M) denote the topology (on M∗M^*) of pointwise convergence on M (K/A being given the discrete topology). Show that, if N is a submodule of M, σ(N0,M/N)\sigma(N^0, M/N) is induced on N0N^0 by σ(M∗,M)\sigma(M^*, M) and that σ(M∗/N0,N)\sigma(M^*/N^0, N) is the quotient by N0N^0 of the topology σ(M∗,M)\sigma(M^*, M). (For the second point, note that, if P is a submodule of M such that N⊂PN \subset P, the dual of P/N is identified with N0/P0N^0/P^0). If M=lim⁡⟶MαM = \lim_{\longrightarrow} M_\alpha, the topology σ(M∗,M)\sigma(M^*, M) is the inverse limit of the topologies σ(Mα∗,Mα)\sigma(M^*_\alpha, M_\alpha).

(e) The topologies σ(K,K)\sigma(K, K) and σ(A,K/A)\sigma(A, K/A) are the x-adic topologies; the topologies σ(A/πnA,A/πnA)\sigma(A/\pi^n A, A/\pi^n A) and σ(K/A,A)\sigma(K/A, A) are the discrete topologies. Deduce that for every A-module M, the module M∗M^* with σ(M∗,M)\sigma(M^*, M) is linearly compact (Chapter III, § 2, Exercise 15; consider M as a quotient module of a free A-module).

(f) Let M, N be two A-modules; for every homomorphism u:M→Nu : M \to N, let tu^t u denote the homomorphism Hom(u,1K/A)\mathrm{Hom}(u, 1_{K/A}) from N∗N^* to M∗M^* such that

(tu(w))(x)=w(u(x)) (^t u(w))(x) = w(u(x))
for all x∈Mx \in M and all w∈N∗w \in N^*; show that tu^t u is continuous for the topologies σ(N∗,N)\sigma(N^*, N) and σ(M∗,M)\sigma(M^*, M). If uu is the endomorphism x↦πxx \mapsto \pi x of M, tu^t u is the endomorphism w↦πww \mapsto \pi w of M∗M^*. For every submodule P of M, (u(P))0=tu(P0)(u(P))^0 = ^t u(P^0).

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.