Bourbaki

Exercise 21, § 1

Commutative Algebra, VII, 551

An integral domain AA is called pseudo-Bezoutian (resp. pseudo-principal) if, in the notation of Exercise 5, the group K∗/UK^*/U is lattice-ordered (completely lattice ordered). Every Bezoutian \* (resp. factorial) \* domain is pseudo-Bezoutian (resp. pseudo-principal) . Every pseudo-principal domain is pseudo-Bezoutian. A valuation ring whose order group is R\mathbf{R} is pseudo-principal but not a principal ideal domain. Every pseudo-Bezoutian (resp. pseudo-principal) domain is integrally closed (resp. completely integrally closed) (use Exercise 6). \ Every Noetherian pseudo-Bezoutian domain is factorial. \* Give an example of an integrally closed Noetherian (and therefore Krull) domain which is not pseudo-Bezoutian (cf. Exercise 2). If AA is pseudo-Bezoutian, so is S−1AS^{-1}A for every multiplicative subset SS of AA such that 0∉S0 \notin S (use Chapter II, § 2, Exercise 1).

Solution

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Transcribed from the printed volume. Not translated.