Bourbaki

Exercise 30, § 1

Commutative Algebra, VII, 554

Bourbaki marks this one as harder than the rest.

An integral domain is called regularly integrally closed if, in the monoid D(A), every finitely generated divisor (Exercise 11) is a regular element. Every completely integrally closed domain is regularly integrally closed; every pseudo-Bezoutial domain (Exercise 2I) is regularly integrally closed. (a) If A is regularly integrally closed and d,d′,d′′d, d', d'' are three finitely generated divisors, the relation d+d′′≤d′+d′′d + d'' \leq d' + d'' implies d≤d′d \leq d'. (b) Deduce from (a) that, for an integral domain A to be regularly integrally closed, it is necessary and sufficient that, for every fractional ideal a of A such that div(a) is a finitely generated divisor, a: a=Aa = A; in particular A is integrally closed (Exercise6 (b)). (Use the fact that A: (bc) = (A: b) : c for two fractional ideals b, c of A, taking b=a,c=A:ab = a, c = A: a.) Moreover, div(a) is then invertible in D(A).

(c) Let AA be a regularly integrally closed domain and KK its field of fractions; the monoid Df(A)D_f(A) of finitely generated divisors of AA generates in D(A)D(A) a lattice-ordered group Gf(A)G_f(A). For every polynomial p∈K[X]p \in K[X], let d(p)d(p) denote the divisor of the fractional ideal of AA generated by the coefficients of pp; for every rational function r=p/qr = p/q of K(X)K(X), where p,qp, q are in K[X]K[X] and q≠0q \neq 0, d(p)−d(q)d(p) - d(q) is well defined on Gf(A)G_f(A) (independently of the expression of rr as a quotient of two polynomials); it is denoted by d(r)d(r) (cf. Exercise 12 (c)). If we then write γ(r)=((r),d(r))\gamma(r) = ((r), d(r)), where (r)(r) is the fractional principal ideal of K[X]K[X] generated by rr, yy is an isomorphism of the ordered group P∗(A[X])\mathscr{P}^*(A[X]) (notation of § 3, no. 2) onto a subgroup of the product ordered group

P∗(K[X])×Gf(A)⊂P∗(K[X])×D(A). \mathscr{P}^*(K[X]) \times G_f(A) \subset \mathscr{P}^*(K[X]) \times D(A).

Deduce that A[X]A[X] is a regularly integrally closed domain and that Df(A[X])D_f(A[X]) is isomorphic to P∗(K[X])×Df(A)\mathscr{P}^*(K[X]) \times D_f(A) (use (a) and (b) and Exercise 29 (b)).

(d) Let BB be an integrally closed domain, KK its field of fractions and AA the subring of the polynomial ring K[X,Y]K[X, Y] consisting of the polynomials whose constant term belongs to BB. Show that, if B≠KB \neq K, AA is integrally closed but not regularly integrally closed (show that the divisor inf⁡(div⁡(X),div⁡(Y))\inf(\operatorname{div}(X), \operatorname{div}(Y)) corresponds to a divisorial ideal aa such that a:a≠Aa : a \neq A).

Solution

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