Bourbaki

Exercise 12, § 2

Algebra, I, 128

Bourbaki marks this one as harder than the rest.

Under a multiplicative law on E, let a∈Ea \in E be such that γa\gamma_a is surjective. (a) Show that, if there exists uu such that ua=aua = a, then ux=xux = x for all x∈Ex \in E. (b) For an element b∈Eb \in E to be such that baba is left cancellable, it is necessary and sufficient that γa\gamma_a be surjective and that bb be left cancellable.

Solution

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Transcribed from the printed volume. Not translated.