Exercise 26, § 6
Algebra, I, 153
Bourbaki marks this one as harder than the rest.
Let be a finite group. is called supersolvable if there exists a composition series of consisting of normal subgroups of such that the quotients are cyclic. (a) Show that every subgroup, every quotient group and every finite product of supersolvable groups is supersolvable. (b) Show that nilpotent supersolvable solvable and that the converse implications are false.
(c) Suppose G is supersolvable. Show that, if , there exists a normal subgroup C of G which is cyclic of prime order. Show that the derived group D(G) of G is nilpotent. Show that every subgroup of G distinct from G which is maximal is of prime index.
(d) A finite group G is bicyclic if there exist two elements of G such that, if and denote the cyclic subgroups generated by and respectively, then . Show that every bicyclic group is supersolvable. (Reduce it to proving that there exists in G a normal cyclic subgroup . Attention may be confined to the case where ; let be the orders of and respectively; by considering the elements , where , show that there exists an integer s such that and ; the set of with this property is the desired cyclic subgroup N.)
Solution
No solution has been written yet.