Bourbaki

Exercise 28, § 6

Algebra, I, 154

Bourbaki marks this one as harder than the rest.

Let G be a finite group and pp a prime number. An element s∈Gs \in G is called p-unipotent (resp. p-regular) if its order is a power of pp (resp. not divisible by pp).

(a) Let x∈Gx \in G. Show that there exists a unique ordered pair (u,t)(u, t) of elements of G satisfying the following conditions: uu is p-unipotent, tt is p-regular, x=ut=tux = ut = tu. (Consider first the case where G is the cyclic group generated by xx.)

(b) Let P be a Sylow pp-group of G, C its centralizer and E the set of p-regular elements of G. Show that

Card⁡(E)≡Card⁡(E∩C)(modp). \operatorname{Card}(E) \equiv \operatorname{Card}(E \cap C) \pmod{p}.

Deduce that Card⁡(E)≢0(modp)\operatorname{Card}(E) \not\equiv 0 \pmod{p}. (Argue by induction on Card⁡(G)\operatorname{Card}(G) and reduce it to the case where C=GC = G; then use (a) to show that Card⁡(E)=(G:P)\operatorname{Card}(E) = (G : P).)

Solution

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Transcribed from the printed volume. Not translated.