Bourbaki

Exercise 33, § 6

Algebra, I, 155

Bourbaki marks this one as harder than the rest.

Let G be a pp-group and A its automorphism group. (a) Let (Gi)0⩽i⩽n(G_i)_{0 \leqslant i \leqslant n} be a composition series of G such that (Gi:Gi+1)=p(G_i : G_{i+1}) = p for

† In fact this case is impossible, as has been shown by Feit and Thompson, Pac. J. of Math., 13 (1963), 775–1029.

0 \leq i \leq n - 1. Let P be the subgroup of A consisting of the automorphisms u such that, for all i and all x \in G_i, u(x)x^{-1} \in G_{i+1}. Show that, if an element u \in P is of order prime to p, then u = 1 (argue by induction on n). Deduce that P is a p-group.

(b) Conversely, let P be a p-subgroup of A. Show that there exists a composition series (Gi)0≤i≤n(G_i)_{0 \leq i \leq n} of G which is stable under P and such that (Gi:Gi+1)=p(G_i : G_{i+1}) = p for 0≤i≤n−10 \leq i \leq n - 1; show that the G_i may be chosen to be normal in G.

Solution

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Transcribed from the printed volume. Not translated.