Exercise 15, § 9
Algebra, I, 177
Bourbaki marks this one as harder than the rest.
Let A be a non-commutative ring with no divisors of 0. A is said to admit a field of left fractions if it is isomorphic to a subring B of a field K such that every element of K is of the form , where .
(a) Let be the set of elements in A. For A to admit a field of left fractions, it is necessary that the following condition be fulfilled: (G) for all , there exist and such that . (b) Suppose conversely that condition (G) is fulfilled. Show that in the set the relation R between and which states "for every ordered pair of elements such that is an equivalence relation.
Let be two elements of , and their respective classes (mod. R). For every ordered pair such that , show that the class (mod. R) of depends only on the classes and ; if it is denoted by , a law of composition is defined on the set . If is the set of elements of K distinct from the class 0 of elements of , , with the law induced by the above law, is a group.
For every element , the elements , where runs through , define an isomorphism of A (with multiplication alone) onto a subring of K. Identifying A with its image under this isomorphism, the class (mod. R) of an ordered pair is identified with the element .
This being so, if is an element of K and 1 denotes the unit element of , then denotes the element , which does not depend on the representation of in the form . We then write and, for , . Show that the addition and multiplication thus defined on K determine on that set a field structure which extends the ring structure on A; in other words, condition (G) is sufficient for A to admit a field of left fractions.
Solution
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