Exercise 35, § 7
Algebra, II, 407
Bourbaki marks this one as harder than the rest.
(a) Let be a field and a -bimodule. Suppose that the dimensions of , as a left and right vector space over , are equal to the same finite number . Show that there exists a family of elements of , which is a basis for each of the two vector space structures on . (Note that if is a family of elements of , which is free for each of the two vector space structures on and is the left vector subspace and the right vector subspace generated by , either , or and are non-empty; in the latter case, if , forms with the a family of elements which is free for each of the two vector space structures on .)
(b) Let be a subbimodule of , whose two vector space structures over have the same dimension . Show that there exists a family of elements of which is a basis of for each of its vector space structures and such that is a basis of for each of its two vector space structures (same method).
(c) Let be a family of elements of , which is free for each of the two vector space structures on . Let (resp. ) be the hyperplane generated by the in considered as a left (resp. right) vector space.
Show that if (resp. ), then necessarily (note that if , the set of such that is a left ideal).
Solution
No solution has been written yet.