Bourbaki

Exercise 1, § 8

Algebra, II, 409

Let K be a field, K' a subfield of K and V a non-zero right vector space over K.

(a) Let V' be a K'-structure on V. Show that K' is equal to the set of μ∈K\mu \in K such that, for all x∈V′x \in V', xμ∈V′x\mu \in V'.

(b) Let Γ′\Gamma' be the group of automorphisms of K leaving invariant the elements of K'. Show that if there exists no element of K not belonging to K' and invariant under all the automorphisms σ∈Γ′\sigma \in \Gamma', there exists no element of V not belonging to V' and invariant under every bijective dimorphism of V (relative to an automorphism of K) which leaves invariant all the elements of V'.

(c) Conversely, let E be a subset of V and G the group of bijective dimorphisms of V leaving invariant all the elements of E; for all u∈Gu \in G, let σu\sigma_u be the corresponding automorphism of K and let Γ\Gamma be the group of automorphisms of K the image of G under the homomorphism u↦σuu \mapsto \sigma_u. Suppose that G contains no automorphism of V distinct from the identity automorphism and that there exists no element of V not belonging to E and invariant under all the dimorphisms u∈Gu \in G. Show that if K' is the subfield of elements of K invariant under all the automorphism σ∈Γ\sigma \in \Gamma, E is a K'-structure on V. (Prove first that E is an additive subgroup of V containing a basis of V; let K'' be the set of elements μ∈K\mu \in K such that the relation x∈Ex \in E implies xμ∈Ex\mu \in E. Show that the elements of K'' are invariant under all σ∈Γ\sigma \in \Gamma and that K'' is a subfield of K; deduce that E is a K''-structure on V.)

Solution

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