Bourbaki

Chapter III

Tensor Algebras, Exterior Algebras, Symmetric Algebras

Recall the exponential notation introduced in Chapter I, of which we shall make frequent use (I, § 7, no. 8):

Let (xλ)λ∈L(x_\lambda)_{\lambda \in L} be a family of pairwise permutable elements of a ring AA; for every mapping α:L→N\alpha : L \to N of finite support we shall write

xα=∏λ∈Lxλα(λ). x^\alpha = \prod_{\lambda \in L} x_\lambda^{\alpha(\lambda)}.

If β\beta is another mapping of LL into NN of finite support, α+β\alpha + \beta denotes the mapping

λ↦α(λ)+β(λ) \lambda \mapsto \alpha(\lambda) + \beta(\lambda)

of LL into NN; with this law of composition the set N(L)N^{(L)} of mappings of LL into NN of finite support is the free commutative monoid derived from LL and

xαxβ=xα+β. x^\alpha x^\beta = x^{\alpha + \beta}.

For all α∈N(L)\alpha \in N^{(L)}, we write ∣α∣=∑λ∈Lα(λ)∈N|\alpha| = \sum_{\lambda \in L} \alpha(\lambda) \in N; then ∣α+β∣=∣α∣+∣β∣|\alpha + \beta| = |\alpha| + |\beta|; ∣α∣|\alpha| is called the order of the "multiindex" α\alpha. For all λ∈L\lambda \in L, let δλ\delta_\lambda denote the element of N(L)N^{(L)} such that δλ(λ)=1\delta_\lambda(\lambda) = 1, δλ(μ)=0\delta_\lambda(\mu) = 0 for μ≠λ\mu \neq \lambda (Kronecker index); the δλ\delta_\lambda for λ∈L\lambda \in L are the only elements of N(L)N^{(L)} of order 1. N(L)N^{(L)} is given the ordering induced by the product ordering on NLN^L, so that the relation α≤β\alpha \leq \beta is equivalent to "α(λ)≤β(λ)\alpha(\lambda) \leq \beta(\lambda) for all λ∈L\lambda \in L"; then the multiindex λ↦β(λ)−α(λ)\lambda \mapsto \beta(\lambda) - \alpha(\lambda) is denoted by β−α\beta - \alpha, so that it is the unique multiindex such that α+(β−α)=β\alpha + (\beta - \alpha) = \beta. For all α∈N(L)\alpha \in N^{(L)}, there are only a finite number of multiindices β≤α\beta \leq \alpha; the δλ\delta_\lambda are the minimal elements of the set N(L)−{0}N^{(L)} - \{0\}; the relation α≤β\alpha \leq \beta implies ∣α∣≤∣β∣|\alpha| \leq |\beta| and if both α≤β\alpha \leq \beta and ∣α∣=∣β∣|\alpha| = |\beta|, then α=β\alpha = \beta.

Finally, we write α!=∏λ∈L(α(λ))!\alpha! = \prod_{\lambda \in L} (\alpha(\lambda))!, which is meaningful since 0!=10! = 1.

From § 4 to § 8 inclusive, AA denotes a commutative ring and, unless otherwise stated, the algebras considered are assumed to be associative and unital and the algebra homomorphisms are assumed to be unital.

Transcribed from the printed edition, 1998, Springer. Not translated.