Bourbaki

Exercise 3, § 10

Algebra, III, 645

Bourbaki marks this one as harder than the rest.

Let K be a field, commutative or otherwise, E the left vector space Ks(N)K_s^{(\mathbf{N})} and let (en)n∈N(e_n)_{n \in \mathbf{N}} be the canonical basis of this space. On the other hand let σ\sigma be an endomorphism of K and dd a (σ,1K)(\sigma, 1_K)-derivation (Exercise 1) of K into itself, in other words an additive mapping of K into itself such that

d(ξη)=(dξ)σ(η)+ξ(dη). d(\xi\eta) = (d\xi)\sigma(\eta) + \xi(d\eta).

The elements of E are linear combinations of products αnen\alpha_n e_n and a multiplication is defined on E (Z\mathbf{Z}-bilinear mapping of E×EE \times E into E) by the conditions

(αen)(βem)=(αen−1)(σ(β)em+1+(dβ)em) for n≥1(αe0)(βem)=(αβ)em. \begin{align*} (\alpha e_n)(\beta e_m) &= (\alpha e_{n-1})(\sigma(\beta)e_{m+1} + (d\beta)e_m) \text{ for } n \geq 1 \\ (\alpha e_0)(\beta e_m) &= (\alpha \beta)e_m. \end{align*}
Thus an (in general non-commutative) ring structure is defined on E with e0e_0 as unit element (identified with the element 1 of K). If we write X=e1X = e_1, then en=Xne_n = X^n for n≥1n \geq 1, so that the elements of E can be written as
α0+α1X+⋯+αnXn, \alpha_0 + \alpha_1 X + \cdots + \alpha_n X^n,
with the multiplication rule
Xα=σ(α)X+(dα)forα∈K. X \alpha = \sigma(\alpha)X + (d\alpha) \quad \text{for} \quad \alpha \in K.
This ring is denoted by K[X;σ,d]K[X; \sigma, d] and is called the ring of non-commutative polynomials in X with coefficients in K, relative to σ\sigma and dd. For a non-zero element z=∑jαjXjz = \sum_j \alpha_j X^j of E, the degree deg⁡(z)\deg(z) is the greatest integer jj such that αj≠0\alpha_j \neq 0.

(a) Show that if u,vu, v are two elements ≠0\neq 0 of E, then:

uv≠0anddeg⁡(uv)=deg⁡(u)+deg⁡(v); uv \neq 0 \quad \text{and} \quad \deg(uv) = \deg(u) + \deg(v);
deg⁡(u+v)≤sup⁡(deg⁡(u),deg⁡(v))if u+v≠0. \deg(u + v) \leq \sup(\deg(u), \deg(v)) \quad \text{if } u + v \neq 0.
Moreover, if deg⁡(u)≥deg⁡(v)\deg(u) \geq \deg(v), there exist two elements w,rw, r of E such that u=wv+ru = wv + r and, either r=0r = 0, or deg⁡(r)<deg⁡(v)\deg(r) < \deg(v) ("Euclidean division" in E).

(b) Conversely, let R be a ring such that there exists a mapping u↦deg⁡(u)u \mapsto \deg(u) of the set R′R' of elements ≠0\neq 0 of R into N\mathbf{N}, satisfying the conditions of (a). Show that the set K consisting of 0 and the non-zero elements u∈Ru \in R such that deg⁡(u)=0\deg(u) = 0 is a (not necessarily commutative) field. If K≠RK \neq R and xx is an element of R for which the integer deg⁡(x)>0\deg(x) > 0 is the smallest possible, show that every element of R can be written uniquely in the form ∑iαixi\sum_i \alpha_i x^i with αi∈K\alpha_i \in K. (To see that every element of R is of this form, argue by reductio ad absurdum by considering an element u∈Ru \in R which is not of this form and for which deg⁡(u)\deg(u) is the smallest possible.) Prove that there exist an endomorphism σ\sigma of K and a (σ,lK)(\sigma, l_K)-derivation dd of K such that xα=σ(α)x+dαx \alpha = \sigma(\alpha)x + d\alpha for all α∈K\alpha \in K. Deduce that R is isomorphic to a field or a ring K[X;σ,d]K[X; \sigma, d].

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.