Bourbaki

Exercise 3, § 13

Algebra, V, p. 171

Let K be an imperfect field and E an algebraic extension of K of finite degree. For an element x∈Ex \in E to exist such that E=K(x)E = K(x) it is necessary and sufficient that the degree of imperfection of E over K (Ex. 1) should be 0 or 1. (To see that the condition is sufficient, note that if E, is the relative separable closure of K in E, we have E=Es(α)E = E_s(\alpha) and Es=K(β)E_s = K(\beta) and if a∉Esa \notin E_s, consider the conjugates of α+cβ\alpha + c\beta over K, for c∈Kc \in K.)

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