Bourbaki

Exercise 4, § 13

Algebra, V, p. 171

Let K be a field of characteristic p>0p > 0 and E an algebraic extension of K of finite degree. If r>0r > 0 is the degree of imperfection of E over K (Ex. 1), show that rr is the least cardinal of sets S such that E=K(S)E = K(S). (To see that E can be generated by rr of its elements note that if E, is the relative separable closure of K in E, then there exist r elements a, (1≤i≤r)(1 \leq i \leq r) of E such that E=Es(a1,...,ar)E = E_s(a_1, ..., a_r), and use Ex. 3.)

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