Bourbaki

Exercise 13, § 3

Algebra, V, p. 149

It is set in small type as supplementary.

Let KK be a field, P(T,X)=a0(T)Xn+a1(T)Xn−1+…+an(T)P(T, X) = a_0(T)X^n + a_1(T)X^{n-1} + \ldots + a_n(T) a polynomial in K[T,X]K[T, X]; suppose that: 1" the polynomial a0a_0 is not divisible by TT; 2" each of the polynomials a1,...,ana_1, ..., a_n is divisible by TT; 3" the polynomial ana_n is not divisible by T2T^2. Show that under these conditions PP, as polynomial of K(T)[X]K(T)[X], is irreducible (argue by contradiction, using Ex. 10).

\* 11) With the notation as in Ex. 11, show that if we take g(X)=Xg(X) = X and h(X)=Xn+X+1 (n≥2)h(X) = X^n + X + 1 \ (n \geq 2), the polynomial (g(X)h(x)−h(X)g(x))/(X−x)(g(X)h(x) - h(X)g(x))/(X-x) of K(x)[X]K(x)[X] is irreducible (use Ex. 13).

\* 15) Give an example of a field K containing two subfields K1,K2K_1, K_2 such that K is algebraic over K1K_1 and over K2K_2, but not over K1∩K2K_1 \cap K_2. (Take K=Q(T)K = \mathbf{Q}(T), K1=Q(T2)K_1 = \mathbf{Q}(T^2), and K2=Q(T2−T)K_2 = \mathbf{Q}(T^2 - T). Verify that [K:K1]=2[K : K_1] = 2, [K:K2]=2[K : K_2] = 2 and K1∩K2=QK_1 \cap K_2 = \mathbf{Q}. To do this note that an element f(T)f(T) of K1∩K2K_1 \cap K_2 satisfies the conditions f(−T)=f(T)f(-T) = f(T) and f(1−T)=f(T)f(1 - T) = f(T).)

Solution

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