Bourbaki

Exercise 2, § 3

Algebra, V, p. 147

Let (Ei)i∈I(E_i)_{i \in I}, be a family of extensions of a field K, contained in an extension L of K. If FiF_i is the relative algebraic closure of K in EiE_i, show that the relative algebraic closure of K in E=⋂i∈IEiE = \bigcap_{i \in I} E_i is F=⋂i∈IFiF = \bigcap_{i \in I} F_i.

Solution

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Transcribed from the printed volume. Not translated.