Bourbaki

Exercise 16, § 2

Algebra, VI, p. 41

Let K be a maximal ordered field and let

g(T)=a0+a1T+⋯+anTn g(T) = a_0 + a_1 T + \cdots + a_n T^n

be a nonzero polynomial in K[T] whose roots all lie in K. Show that for any polynomial f∈K[T]f \in K[T], the number of roots of the polynomial

a0f(T)+a1f′(T)+a2f′′(T)+…+anf(n)(T) a_0 f(T) + a_1 f'(T) + a_2 f''(T) + \ldots + a_n f^{(n)}(T)

which do not belong to K, counted with multiplicity, is at most equal to the number of roots of ff, counted with multiplicity, which do not belong to K (use Ex. 12 for n=1n = 1, then proceed by induction). Deduce that the polynomial

a0+a11!T+a22!T2+⋯+ann!Tn a_0 + \frac{a_1}{1!} T + \frac{a_2}{2!} T^2 + \cdots + \frac{a_n}{n!} T^n

has all its roots in K.

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.