Exercise 32, § 2
Algebra, VI, p. 45
Bourbaki marks this one as harder than the rest.
Let A be an algebraically closed field of characteristic 0. a) The only elements of finite order in the group Aut(A) of automorphisms of A are the identity element and elements of order 2 (involutions of A) ; these latter correspond bijectively to the maximal ordered subfields E of A such that , that is (cf. Ex. 31). If a is an involution of A and E is the fixed subfield of a , then the group Aut(E) of automorphisms of E is isomorphic to the quotient , where is the centraliser of in Aut(A). b) If A is algebraic over its prime field Q then any two involutions of A are conjugate in Aut(A) and the centraliser of an involution a is ; the group Aut(A) and the set of involutions of A have the cardinality of the continuum, and the centre of Aut(A) is . c) If A has finite transcendence degree over Q, show that the centraliser of any involution a of A is countable (observe that the fixed subfield E of a is countable, and any automorphism of E which fixes the elements of some transcendence basis for E over Q is the identity). If deg . tr_QA = n, show that there exist at least n + 1 conjugacy classes of involutions of A (if E is maximal orderable with , consider the transcendence degree over Q of the subfield of E consisting of elements fixed by Aut(E), and use Ex. 24). d) If A has infinite transcendence degree m over Q, show that there exist involutions of A such that Card Card (use Ex. 24 to show that there exist maximal orderable fields E such that deg . tr_QE = m, such that for any subset M of any transcendence basis B for E over Q, there exists an automorphism of E such that for and for ). e) If deg . tr_QA = 1, show that there is only one conjugacy class of involutions of A whose centralisers are infinite. (If E is a maximal orderable extension of Q of transcendence degree 1 such that Aut(E) is nontrivial, use Ex. 24 to show that E cannot be comparable to Q ; if t is infinitely large with respect to Q, show that so is for any automorphism of E, and that conversely if is infinitely large with respect to Q then there exists an automorphism of E such that , using Ex. 15 of VI, p. 40.) f) Let be an automorphism of A which commutes with all the involutions of A. Show that if a is transcendental over Q then a and are algebraically dependent over Q. (Consider two elements b, c of A such that and observe that there exists a maximal orderable extension E such that and b, c are in E ; obtain a contradiction by noticing that ) g) Deduce from f) that for every element a transcendental over Q (consider a maximal ordered extension E of contained in A, algebraic over and comparable to Q, using Ex. 24). Conclude that u is necessarily the identity (observe that if a is algebraic over and is transcendental over Q then is transcendental over Q).
Solution
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