Bourbaki

Exercise 40, § 2

Algebra, VI, p. 47

Let K be an ordered field. Make the field of formal power series E=K((X))E = K((X)) an ordered field by taking the elements >0> 0 to be the formal power series ∑n=h∞rnXn\sum_{n=h}^{\infty} r_n X^n whose nonzero coefficient of least degree is >0> 0. a) Show that if L=K(X)L = K(X) is the subfield of E consisting of rational functions in one indeterminate, then E=L~E = \tilde{L} (Ex. 36) up to isomorphism of ordered fields (observe that for every element a>0a > 0 of L there exists an integer n>0n > 0 such that 0<Xn<u0 < X^n < u). b) Suppose that K is maximal ordered. Show that the union F of the fields K((X1/n))K((X^{1/n})) (ordered in the same way as E) is an ordered algebraic extension of E which is maximal ordered (use Ex. 2 of V, p. 150). c) Show that the field F~\tilde{F} (Ex. 36) is the field of formal series ∑αrXr\sum \alpha_r X^r, where r runs through the set Q\mathbf{Q} of rational numbers, and where ar∈Ka_r \in K and the set of r such that ar≠0a_r \neq 0 is an increasing sequence which is either finite or tends to +∞+\infty; order this field in the same manner as E. In particular F~≠F\tilde{F} \neq F.

Solution

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