Exercise 10, § 2
Algebra, VII, p. 56
Bourbaki marks this one as harder than the rest.
u) Let be a -primary module with no nonzero elements of infinite height and let be a pure submodule of generated by a maximal pseudofree family of elements of (Ex. 4 and 7, b)). Show that is a divisible module (argue by contradiction, applying Ex. 8, c), Ex. 7, c), Ex. 7, b), and finally Ex. 4, c)).
b) Consider the metrisable topology on M defined by taking as a basis of neighbourhoods of 0 the submodules for all integers (Gen. Top., III, p. 5). Then the quotient of M by a submodule P is divisible if and only if P is everywhere dense in M under the topology .
c) Let be two submodules of M which are pure, everywhere dense in M under the topology , and direct sums of cyclic submodules. Show that and are isomorphic (notice that is isomorphic to for all n).
d) Let M be the completion of M with respect to the topology (Gen. Top., III, p. 24). Show that is a strict morphism from M onto for all , that is an open and closed submodule, and the closure of , for all , and that the quotient modules , are isomorphic.
e) Let M be the torsion submodule of : show that M is a =-primary module, that , and that M is a pure submodule of M.
f) Suppose the -primary module M is the direct sum of a family of cyclic submodules. Then is discrete if and only if the annihilator of M is 0. In this case, let E be the product module and let F be the submodule of E consisting of elements all but countably many of whose coordinates are zero; show that M can then be identified (as a non-topological module) with the submodule of F consisting of such that, for each integer , there are only finitely many indices for which . Then show that the four modules M, , M and F are distinct. Deduce that M is not a direct sum of cyclic modules (use e)), and that it is not a direct sum of indecomposable modules (notice that contains no elements of infinite height, and apply Ex. 8, c)).
Solution
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