Bourbaki

Exercise 12, § 2

Algebra, VII, p. 57

Bourbaki marks this one as harder than the rest.

A π\pi-primary module M is a direct sum of cyclic submodules if and only if there exists a pseudofree subset H in M such that, if N is the pure submodule of M generated by H, then M(π)=N(π)M(\pi) = N(\pi). b) The module M is a direct sum of cyclic submodules if and only if M is the union of an increasing sequence (Pk)(P_k) of submodules, such that the heights in M of the nonzero elements in each PkP_k are bounded. (To see that the condition is sufficient, use a) and Ex. 11, b).) c) Deduce from b) that if M is a direct sum of cyclic submodules, then every submodule of M is a direct sum of cyclic submodules. d) Let M be a π\pi-primary module with no elements of infinite height, having a countable system of generators (xi)(x_i). Show that M is a direct sum of cyclic submodules (if

P_k is the submodule generated by x, for i ≤ k, then apply b) to the increasing sequence (P_k), using Ex. 5 applied to the decreasing sequence (P_k ∩ π^iM) (for fixed k)). e) Let M be a τ-primary module having a countable system of generators. Then M is a direct sum of indecomposable submodules if and only if the submodule N of elements of infinite height in M is pure (use d) and Ex. 7, c)).

Solution

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Transcribed from the printed volume. Not translated.