Bourbaki

Exercise 2, § 2

Algebra, VII, p. 54

Let A be a principal ideal domain, let π be an irreducible element of A and let M be a π-primary module; show that for all x ∈ M and all a ∈ A not a multiple of π, there exists a unique y ∈ M such that x = αy (use the Bezout identity); put y = α−1x\alpha^{-1}x. Deduce that, if A(π)A_{(\pi)} denotes the principal ideal domain consisting of elements β/α\beta/\alpha of the field of fractions of A, such that α, β ∈ A and α is not a multiple of π (VII, p. 48, Ex. 4), then there exists a unique A(π)A_{(\pi)}-module structure on M such that restriction of the ring of operators to A gives the original A-module structure on M. The A(π)A_{(\pi)}-module thus defined is said to be canonically associated to M; its submodules are identical to the A-submodules of M.

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Transcribed from the printed volume. Not translated.