Bourbaki

Exercise 6, § 2

Algebra, VII, p. 55

Let M be a torsion module over a principal ideal domain A, which is not finitely generated, but all of whose proper submodules are finitely generated. Show that there exists an irreducible element τ1\tau_1 of A such that M is isomorphic to the τ\tau-primary component UπU_{\pi} of the module U=K/AU = K/A (Ex. 3, c)). (First of all show that M cannot have more than one nonzero π\pi-primary component, and hence is a τ\tau-primary module for some irreducible element τ∈A\tau \in A. Then show that M=πMM = \pi M by observing that M/πMM/\pi M could not be finitely generated if it were nonzero; but M/πMM/\pi M is a vector space over the field A/πAA/\pi A, and would contain a proper subspace which was not finitely generated.)

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Transcribed from the printed volume. Not translated.