Bourbaki

Exercise 24, § 1

Tag 001K, permanent. Cite it as [Bourbaki, Tag 001K].

Algebra, VIII, p. 21

Bourbaki marks this one as harder than the rest.

Let G be a group, ee its identity element, and A a nonzero commutative ring. Denote the algebra of the group G over A by A[G] (III, §2, No. 6, p. 446). a) Let I be a finite set, (Gi)i∈I(G_i)_{i\in I} a family of subgroups of G, and (gi)i∈I(g_i)_{i\in I} a family of elements of G. Prove that if G is the union of the family (giGi)i∈I(g_iG_i)_{i\in I}, one of the subgroups GiG_i has finite index in G.

b) Suppose that every conjugacy class in G distinct from {e}\{e\} is infinite and that the ring A is an integral domain. Prove that if a\mathfrak{a} and b\mathfrak{b} are two nonzero two-sided ideals of the ring A[G], we have ab≠0\mathfrak{a}\mathfrak{b}\not= 0. (Choose elements a=∑agga=\sum a_gg and b=∑bggb=\sum b_gg in a\mathfrak{a} and b\mathfrak{b} with ae≠0a_e\not= 0 and be≠0b_e\not= 0. Using a), prove that, if necessary replacing aa with hah−1hah^{-1} for suitable h∈Gh\in G, we may assume that agbg−1=0a_gb_{g^{-1}}= 0 for every g≠eg\not=e in G.) ∗*c) Prove that the ring A[G] is left (resp. right) Artinian if and only if the ring A is

Artinian and the group G is finite. (If A[G] is left Artinian, deduce from Theorem 1 of VIII, p. 6 that the group G has finite length; to prove that it is finite, reduce to the case when A is a field and G a simple group, and then use b) and Proposition 1 of VIII, p. 173).∗).*

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