Bourbaki

Exercise 32, § 6

Tag 03UV, permanent. Cite it as [Bourbaki, Tag 03UV].

Theory of Sets, III, 250

Bourbaki marks this one as harder than the rest, it is set in small type as supplementary.

Let (Mn)(M_n), (Pn)(P_n) be two sequences of mutually disjoint finite sets (not all empty), indexed by the set Z\mathbf{Z} of rational integers. Let αn=Card (Mn)\alpha_n = \mathrm{Card}\ (M_n), βn=Card (Pn)\beta_n = \mathrm{Card}\ (P_n). Suppose that there exists an integer k>0k > 0 such that for each n∈Zn \in \mathbf{Z} and each integer l⩾1l \geqslant 1 we have

αn+αn+1+⋯+αn+l⩽βn−k+βn−k+1+⋯+βn+l+k,\alpha_n + \alpha_{n+1} + \cdots + \alpha_{n+l} \leqslant \beta_{n-k} + \beta_{n-k+1} + \cdots + \beta_{n+l+k},
βn+βn+1+⋯+βn+l⩽αn−k+αn−k+1+⋯+αn+l+k.\beta_n + \beta_{n+1} + \cdots + \beta_{n+l} \leqslant \alpha_{n-k} + \alpha_{n-k+1} + \cdots + \alpha_{n+l+k}.

Let M be the union of the family (Mn)(M_n) and let P be the union of the family (Pn)(P_n). Show that there exists a bijection φ\varphi of M onto P such that

φ(Mn)⊂⋃i=n−k−1n+k+1Piandφ−1(Pn)⊂⋃i=n−k−1n+k+1Mi\varphi(M_n) \subset \bigcup_{i=n-k-1}^{n+k+1} P_i \quad \text{and} \quad \overset{-1}{\varphi}(P_n) \subset \bigcup_{i=n-k-1}^{n+k+1} M_i

for each n∈Zn \in \mathbf{Z}. (Consider a total ordering on each Mn\mathrm{M}_n (resp. Pn\mathrm{P}_n) and take M (resp. P) to be the ordinal sum (§ 1, Exercise 3) of the family (Mn)n∈Z(\mathrm{M}_n)_{n \in \mathbf{Z}} (resp. (Pn)n∈Z(\mathrm{P}_n)_{n \in \mathbf{Z}}). If n0n_0 is an index such that Mn0≠∅\mathrm{M}_{n_0} \neq \emptyset, consider the isomorphisms of M onto P which transform the least element of Mn0\mathrm{M}_{n_0} into one of the elements of ⋃j=n0−kn0+kPj\bigcup\limits_{j=n_0-k}^{n_0+k} \mathrm{P}_j, and show that one of these isomorphisms satisfies the required conditions. Let δ\delta be the least of the numbers

βn−k+βn−k+1+⋯+βn+l+k−(αn+αn+1+⋯+αn+l),\beta_{n-k} + \beta_{n-k+1} + \cdots + \beta_{n+l+k} - (\alpha_n + \alpha_{n+1} + \cdots + \alpha_{n+l}),
αn−k+αn−k+1+⋯+αn+l+k−(βn+βn+1+⋯+βn+l)\alpha_{n-k} + \alpha_{n-k+1} + \cdots + \alpha_{n+l+k} - (\beta_n + \beta_{n+1} + \cdots + \beta_{n+l})

for all n∈Zn \in \mathbf{Z} and all l⩾1l \geqslant 1. If n∈Zn \in \mathbf{Z} and l⩾1l \geqslant 1 are such that, for example, βn−k+βn−k+1+⋯+βn+l+k=δ+αn+αn+1+⋯+αn+l\beta_{n-k} + \beta_{n-k+1} + \cdots + \beta_{n+l+k} = \delta + \alpha_n + \alpha_{n+1} + \cdots + \alpha_{n+l}, we may take φ\varphi to be such that the least element of Pn−k\mathrm{P}_{n-k} is the image under φ\varphi of the least element of Mn\mathrm{M}_n.)

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