Exercise 1, § 3
Topological Vector Spaces, I, p. 28
) Show that, if a Hausdorff topological vector space E over a non-discrete valued division ring K is such that every neighbourhood of 0 contains a vector subspace that is not the single point 0, then the topology of E cannot be defined by a norm, In particular, a product of an infinite sequence of Hausdorff topological vector spaces on K, none consisting of the single point 0, has a topology that cannot be defined by a norm. b) Consider the product vector space ; for all , put
Show that the topology of E is defined by the distance , that if , if and that, for all , tends to 0 with .
Solution
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