Exercise 20, § 6
Topological Vector Spaces, II, p. 86
It is set in small type as supplementary.
Let , where A is any infinite set; suppose that F and G are put in separating duality by the bilinear form . a) Let N be an additive subgroup of G; we denote by the subgroup of the such that is an integer for all and by the subgroup of the such that is an integer for all . If is the closure of N for the topology , show that is closed in F for and that (to establish this last point, use GT, VII, § 1.3, prop. 6, projecting N on the finite dimensional coordinate varieties of G). b) Suppose that . Let M be a closed subgroup of F for ; show that if V is the largest vector subspace contained in M, then M is the topological direct sum of V and of a closed subgroup P that is a free -module having an enumerable base. (Consider F as the union of an increasing sequence of finite dimensional vector subspace and apply GT, VII, § 1.2, th. 2 and § 1, exerc. 7.) P is discrete (for the topology induced by ), if, and only if, P is of finite rank. c) Deduce from a) and b) that when , every closed subgroup of G (when G carries the product topology ) can be transformed, by an automorphism of the topological group G, in a product , where I and J are two sets of N without common elements. d) In the space , carrying the topology , show that the subgroup is closed and does not contain any line, even though it is not a free -module (A, VII, p. 59, exerc. 8); the results of b) do not therefore extend when A is not enumerable.
Solution
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