Bourbaki

Exercise 1, § 6

Topological Vector Spaces, III, p. 49

Bourbaki marks this one as harder than the rest.

An exhaustion of a Hausdorff locally convex space is given by a sieve C=(Cn,pn)n≥0C = (C_n, p_n)_{n \geq 0} (GT, IX, § 6, No. 5, def. 8) and, for every n≥0n \geq 0, a mapping ρn\rho_n from CnC_n into the set of all convex and balanced subsets of EE having the following properties: E1) EE is the union of the ϕ0(c)\phi_0(c) where cc ranges over C0C_0; E2) for every nn and every c∈Cnc \in C_n, ϕn(c)\phi_n(c) is the union of the ϕn+1(c′)\phi_{n+1}(c') where c′c' ranges over pn−1(c)p_n^{-1}(c); E3) for every sequence (ck)k≥0(c_k)_{k \geq 0} such that ck∈Ckc_k \in C_k and ck=pk(ck+1)c_k = p_k(c_{k+1}) for all k≥0k \geq 0, there exists a sequence (ϕk)(\phi_k) of numbers >0> 0 such that, for every sequence (xk)(x_k) of points of EE such that xk∈ϕk(ck)x_k \in \phi_k(c_k) and every sequence (λk)(\lambda_k) of real numbers satisfying 0≤λk≤ρk0 \leq \lambda_k \leq \rho_k for all kk, the series ∑k=0∞λkxk\sum_{k=0}^\infty \lambda_k x_k is convergent in EE. a) Under the above hypotheses, show that if in addition the ϕn(c)\phi_n(c) are closed for c∈Cnc \in C_n, then we can assume that the ρk\rho_k have been so chosen that we have ∑k=m∞λkxk∈ϕm(cm)\sum_{k=m}^\infty \lambda_k x_k \in \phi_m(c_m) for all m≥1m \geq 1 (take the ρk\rho_k such that ∑k=0∞ρk≤1\sum_{k=0}^\infty \rho_k \leq 1). b) Suppose that we are given a sieve CC and sequence (ϕn)(\phi_n) of mappings into the set of convex and balanced subsets of EE satisfying E1), E2) and the following condition: E3') for every sequence (ck)k≥0(c_k)_{k \geq 0} such that ck=pk(ck+1)c_k = p_k(c_{k+1}) for all k≥0k \geq 0, there exists a sequence (μk)(\mu_k) of numbers >0> 0 such that, for every sequence (xk)(x_k) of points of EE with xk∈ϕk(ck)x_k \in \phi_k(c_k) for all kk, the sequence of points (μkxk)(\mu_k x_k) is contained in a convex, bounded balanced and semi-complete set in EE. Show that then the condition E3) is also verified (take ρk=2−kμk\rho_k = 2^{-k} \mu_k). A locally convex Hausdorff space is said to be exhaustible if there exists an exhaustion of EE.

Solution

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Transcribed from the printed volume. Not translated.