Exercise 15, § 5
Topological Vector Spaces, IV, p. 70
Let E be a Banach space with a Banach basis (exerc. 14); then there exists a unique sequence in the dual of E such that the expression of every in terms of the Banach basis can be written as .
a) Let be the closed vector subspace of E generated by the for . For every , let denote the norm of the restriction of the linear form to . Show that, for to be a Banach basis of , it is necessary and sufficient that for every , the sequence tends to 0. (Consider the transpose and evaluate the norm .) In this case, the Banach basis is said to be contracting.
b) Suppose that the Banach basis is contracting. Show that for every point of the bidual of E, the sequence of sums is bounded in E (consider the transpose in ). Conversely, for every sequence of scalars such that the sequence of sums is bounded in E, there exists a unique such that for all (use the compactness of a closed ball in for the topology ).
c) A Banach basis in E is said to be complete if, for every sequence of scalars such that the sequence of sums is bounded, the series converges. If is a contracting basis of E, the basis of is complete (use the compactness of a closed ball in for ).
d) In general, the sequence is a Banach basis of the closed subspace of the strong dual of E, generated by the , and there is an injective continuous linear mapping from E into the strong dual of such that for all and all . Show that there exists a constant such that , and that if the basis is complete, then is an isomorphism from E onto the topological vector space .
e) Show that for E to be reflexive, it is necessary and sufficient that the basis is contracting and complete (use b)).
Solution
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