Bourbaki

Exercise 17, § 5

Topological Vector Spaces, IV, p. 71

Bourbaki marks this one as harder than the rest.

a) Let E be a Banach space with an unconditional Banach basis (en)(e_n) (exerc. 16). Show that if the basis (en)(e_n) is not contracting (IV, p. 70, exerc. 15), then there exists a number α>0\alpha > 0, a linear form x′∈E′x' \in E' such that ∥x′∥=1\|x'\| = 1, a strictly increasing sequence of integers (nk)(n_k) and for each kk, an element yky_k which is a linear combination of the eje_j for nk≤j≤nk+1n_k \leq j \leq n_{k+1}, and is such that ∥yk∥≤1\|y_k\| \leq 1 and ⟨yk,x′⟩≥α\langle y_k, x' \rangle \geq \alpha. Deduce that for every finite sequence (λj)1≤j≤m(\lambda_j)_{1 \leq j \leq m} of scalars, we have ∥∑j=1mλjyj∥≥α2K∑j=1m∣λj∣\left\| \sum_{j=1}^m \lambda_j y_j \right\| \geq \frac{\alpha}{2K} \sum_{j=1}^m |\lambda_j| (use exerc. 16, c)). Conclude that there exists a topological vector space isomorphism from ℓ1(N)\ell^1(\mathbf{N}) onto a closed subspace of E. b) Deduce from a) that if the strong dual E′E' of E satisfies the first axiom of countability, then every unconditional basis (en)(e_n) of E is contracting, and hence (en′)(e'_n) is an unconditional basis of E′E' (IV, p. 70, exerc. 15, a)). (Observe that if a closed vector subspace of E is isomorphic to ℓ1(N)\ell^1(\mathbf{N}), then E' cannot satisfy the first axiom of countability.) c) Show that if E has an unconditional basis and if the strong bidual E′′E'' of E satisfies the first axiom of countability, then E is reflexive. (Using IV, p. 51, exerc. 25, note that the strong dual E′E' of E satisfies the first axiom of countability; then use IV, p. 70, exerc. 15, c) and IV, p. 53, exerc. 11.)

Solution

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