Bourbaki

Exercise 13, § 3

Functions of a Real Variable, I, 43

Bourbaki marks this one as harder than the rest.

a) Let ff be a twice differentiable real function on R\mathbf{R}, such that (f(x))2≤a(f(x))^2 \leq a and (f′(x))2+(f′′(x))2≤b(f'(x))^2 + (f''(x))^2 \leq b on R\mathbf{R}; show that

(f(x))2+(f′(x))2≤max⁡(a,b) (f(x))^2 + (f'(x))^2 \leq \max(a, b)
on R\mathbf{R} (argue by contradiction, noting that if the function f2+f′2f^2 + {f'}^2 takes a value c>max⁡(a,b)c > \max(a, b) at a point x0x_0 then there exist two points x1,x2x_1, x_2 such that x1<x0<x2x_1 < x_0 < x_2 and that at x1x_1 and x2x_2 the function f′f' takes values small enough that f2+f′2f^2 + {f'}^2 takes values <c< c; then consider a point of [x1,x2][x_1, x_2] where f2+f′2f^2 + {f'}^2 attains its supremum on this interval).

b) Let ff be a real function nn times differentiable on R\mathbf{R}, and such that (f(x))2≤a(f(x))^2 \leq a and (f(n−1)(x))2+(f(n)(x))2≤b(f^{(n-1)}(x))^2 + (f^{(n)}(x))^2 \leq b on R\mathbf{R}; show that then

(f(k−1)(x))2+(f(k)(x))2≤max⁡(a,b) (f^{(k-1)}(x))^2 + (f^{(k)}(x))^2 \leq \max(a, b)
on R\mathbf{R} for 1≤k≤n1 \leq k \leq n. (Argue by induction on nn; note that, by exerc. 12 the supremum cc of (f′(x))2(f'(x))^2 on R\mathbf{R} is finite; show that one necessarily has c≤max⁡(a,b)c \leq \max(a, b) by reducing to a contradiction: assuming that c>max⁡(a,b)c > \max(a, b) choose the constants λ\lambda and μ\mu so that for the function g=λf+μg = \lambda f + \mu one has ∣g(x)∣≤1, ∣g′(x)∣≤1|g(x)| \leq 1,\ |g'(x)| \leq 1, yet one cannot have (g(x))2+(g′(x))2≤1(g(x))^2 + (g'(x))^2 \leq 1 for all xx.)

Solution

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Transcribed from the printed volume. Not translated.