Bourbaki

Exercise 9, § 3

Functions of a Real Variable, I, 42

With the same notation as in exerc. 8 suppose that ff is nn times differentiable on I but otherwise arbitrary. Let gg be the polynomial of degree n−1n - 1 (with real coefficients) such that at the point xix_i (1≤i≤p1 \leq i \leq p) both gg and its first ni−1n_i - 1 derivatives are respectively equal to ff and its first ni−1n_i - 1 derivatives. Show that we have

f(x)=g(x)+(x−x1)n1(x−x2)n2…(x−xp)npn!f(n)(ξ) f(x) = g(x) + \frac{(x - x_1)^{n_1}(x - x_2)^{n_2} \ldots (x - x_p)^{n_p}}{n!} f^{(n)}(\xi)
where ξ\xi is interior to the smallest interval containing the points xix_i (1≤i≤p1 \leq i \leq p) and xx. (Apply exerc. 8 to the function of tt)
f(t)−g(t)−a(t−x1)n1(t−x2)n2…(t−xp)npn! f(t) - g(t) - a \frac{(t - x_1)^{n_1}(t - x_2)^{n_2} \ldots (t - x_p)^{n_p}}{n!}
where aa is a suitably chosen constant.)

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.