Exercise 13, § 1 Functions of a Real Variable, III, 118 If x,y,a,bx, y, a, bx,y,a,b are > 0, show that xlogxa+ylogyb≥(x+y)logx+ya+b x \log \frac{x}{a} + y \log \frac{y}{b} \geq (x + y) \log \frac{x + y}{a + b} xlogax+ylogby≥(x+y)loga+bx+y with equality only if x/a=y/bx/a = y/bx/a=y/b. Solution No solution has been written yet.