Bourbaki

Exercise 37, § 1

Functions of a Real Variable, III, 124

Let f\mathbf{f} be a regulated vector function on ]0,1[]0, 1[, such that the integral ∫0πf(sin⁡x)dx\int_0^\pi \mathbf{f}(\sin x) dx is convergent. Show that the integral ∫0πxf(sin⁡x)dx\int_0^\pi x \mathbf{f}(\sin x) dx is convergent and that

∫0πxf(sin⁡x)dx=π2∫0πf(sin⁡x)dx. \int_0^\pi x \mathbf{f}(\sin x) dx = \frac{\pi}{2} \int_0^\pi \mathbf{f}(\sin x) dx.

Solution

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Transcribed from the printed volume. Not translated.