Exercise 17, § 4
Integration, IV, p. 125
Bourbaki marks this one as harder than the rest.
Let be the locally compact space defined in GT, I, §9, Exer. 11.
a) Let be a compact subset of the locally convex space equipped with the topology of compact convergence; show that the functions are uniformly bounded on and that there exists such that, for every , all of the functions of are constant. (Argue by contradiction; if the functions of were not uniformly bounded on , there would be an increasing sequence of points of such that , where denotes the set of for ; observe that the sequence is convergent in . Similarly, for every , let be the supremum of the oscillations of all the functions in the interval ; is finite and decreasing, therefore there exists such that is constant for . To see that this constant is zero, argue by contradiction as before, on forming two increasing sequences of points of such that and a sequence of functions in such that .)
In particular, is the direct sum of and .
b) Show that on , every measure has compact support (for every let be the characteristic function of the interval , which is continuous and has compact support; consider on the increasing function ).
c) Deduce from a) and b) that in , the bounded sets for the topology of uniform convergence on the compact subsets of are the bounded sets for the ultrastrong topology (Ch. III, §1, Exer. 15). Show that is not quasi-complete for the topology (consider the measures for ); from this, deduce that for the topology of compact convergence, is neither barreled nor bornological (cf. TVS, III, §4, No. 2, Cor. 4 of Th. 1 and Exer. 18 below).
d) Show that on the topology (the direct limit of the topologies of the Banach spaces ) is identical to the topology of uniform convergence, and that, equipped with this topology, is complete. (Let be a neighborhood of 0 for ; for every , let be the largest number such that contains all of the continuous functions with support contained in and such that . Show that the infimum of in is , by proving that there cannot exist an increasing sequence of points of such that .)
Solution
No solution has been written yet.