Bourbaki

Exercise 18, § 6

Integration, V, p. 111

In Prop. 4 b), the conclusion may fail if one omits the hypothesis that π′\pi' is continuous. (Take T=RT = \mathbf{R}, T′=R‾T' = \overline{\mathbf{R}}, T′′=RT'' = \mathbf{R}; take for μ\mu Lebesgue measure, for π\pi the canonical injection; set π′(x)=x\pi'(x) = x for x∈Rx \in \mathbf{R} and π′(±∞)=0\pi'(\pm \infty) = 0.)

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Transcribed from the printed volume. Not translated.