Appendix
Complements on topological vector spaces
1. Bilinear forms and linear mappings
Let be two pairs of (real or complex) vector spaces in separating duality (TVS, II, §6, No. 1); assume each of these spaces to be equipped with the corresponding weak topology (loc. cit., No. 2); if A and B are any two of these spaces, as usual we denote by the vector space of continuous linear mappings of A into B, and by the vector space of separately continuous bilinear forms on .
For every separately continuous bilinear form on , is a continuous linear form on , therefore there exists one and only one element such that
for (TVS, III, §5, No. 1, (1)). Moreover, this formula shows that the mapping is linear and continuous for the (weak) topologies of and . Conversely, for every continuous linear mapping of into , is a separately continuous bilinear form on , and . One thus defines an isomorphism of onto , said to be canonical.
Similarly, the formula
defines a canonical isomorphism of onto ; and one obviously has the commutative diagram
where is the isomorphism of transposition . In view of the definition of the weak topologies on and , it is moreover immediate that when , and are equipped with the topology of pointwise convergence, the isomorphisms in the preceding diagram are isomorphisms for the topological vector space structures.
Now let be two Hausdorff locally convex spaces, their respective duals; we denote by the spaces equipped with the weakened topologies , , and by the spaces equipped with the weak topologies , . Thus, the preceding remarks establish canonical isomorphisms between the three spaces , and , and also between the three spaces , and . One will observe that is also equal to the space of separately continuous bilinear forms on ( and being equipped with their original topologies), since every continuous linear form on (resp. ) is continuous on (resp. ) and conversely (TVS, II, §6, No. 1 and No. 2, Prop. 3).
Let be the space of continuous bilinear forms on ( and being equipped with their original topologies); then .
Proposition 1
For a bilinear form to belong to , it is necessary and sufficient that there exist a neighborhood of 0 in whose image under is an equicontinuous subset of .
For, to say that is continuous means that there exists a balanced convex neighborhood (resp. ) of 0 in (resp. ) such that for , ; this may be written for , , or also ; whence the proposition, taking into account the fact that every equicontinuous subset of is contained in the polar of a neighborhood of 0 in .
Corollary
If is a continuous bilinear form on , then is a continuous linear mapping of into the strong dual of . If, moreover, and are normed spaces, then .
The first assertion follows from Prop. 1 and the fact that every neighborhood of 0 in absorbs every equicontinuous subset of . If and are normed, then
whence the second assertion.
Interchanging the roles of E and F, one obtains results analogous to Prop. 1 and its corollary for the linear mappings ; we leave to the reader the task of stating them.
2. Some types of spaces having the property (GDF)
We already know that every Fréchet space has the property (GDF) (TVS, I, §3, No. 3, Cor. 5 of Th. 1).
Proposition 2
— Let E be a vector space, a family of locally compact spaces having the property (GDF), and for each let be a linear mapping of into E. If E is equipped with the finest locally convex topology that makes the continuous, then E has the property (GDF).
Let be a linear mapping of E into a Banach space B, such that every limit in of every convergent sequence of points of the graph of also belongs to . It suffices to show that, for every , is continuous on (TVS, II, §4, No. 4, Prop. 5). Now, let be a sequence of elements of having a limit and such that the sequence has a limit . Since is continuous, is a limit of the sequence in E; therefore by hypothesis and, since has the property (GDF), is continuous.
Corollary
— Every quotient space of a locally convex space having the property (GDF) has the property (GDF).
Proposition 3
— The strong dual of a reflexive Fréchet space has the property (GDF).
This is a consequence of Prop. 2 and the following lemma (or TVS, IV, §3, No. 4, Prop. 4):
Lemma
Let F be a Fréchet space, its strong dual, its bidual. If every subset of , bounded for , is contained in the closure (for ) of a bounded subset of F, then is the direct limit of a sequence of Banach spaces.
For, let be a decreasing fundamental sequence of convex, balanced and closed neighborhoods of 0 in F. For every integer , let be the linear subspace of generated by the polar of . In , is an absorbent convex set, therefore its gauge is a norm on ; moreover, is a complete subset of the strong dual (TVS, III, §3, No. 8, Prop. 11); thus , equipped with the norm , is a Banach space (GT, III, §3, No. 5, Cor. 2 of Prop. 9). We are going to show that the strong topology on is the direct limit of these Banach space topologies on the , or again that, for a strongly closed, balanced, convex subset U of to be a strong neighborhood of 0, it is necessary and sufficient that it absorb each of the . It is obvious that this condition is necessary; to see that it is sufficient, it will suffice to prove that U contains a barrel of . Indeed, its polar in will then be bounded for , hence, by hypothesis, will be contained in the closure (for ) of a bounded subset B of F, from which one can conclude that U (which is closed for ) contains the strong neighborhood of 0 (TVS, II, §6, No. 3, Th. 1 and §8, No. 4).
By hypothesis, for every integer there exists a number such that ; let be the convex envelope of the union of the for . Then for every ; let W be the union of the ; W is a convex, balanced, absorbent set contained in , and it will suffice to show that its strong closure (which is a barrel) is contained in U.
Thus, let be a point of not belonging to U. Since each of the is compact for , the same is true of the (TVS, II, §2, No. 6, Prop. 15), and since , there exists an element belonging to the polar of in F such that (TVS, II, §5, No. 3, Prop. 4). The sequence is bounded in F: for, every belongs to some , consequently for , whence our assertion (TVS, IV, §1, No. 1, Prop. 1). Let C be a bounded, balanced convex set in F containing all the ; is then a neighborhood of 0 in , and the polar of in is compact for (TVS, III, §3, No. 4, Cor. 2 of Prop. 4 and No. 5, Prop. 7). Thus one sees that the sequence has a cluster point in for ; obviously and, on the other hand, belongs to the polar of in for every , hence to the polar of W in . From this, one concludes that , hence is not in the closure of W for (TVS, II, §6, No. 3, Th. 1 and §8, No. 4), therefore a fortiori for the strong topology, which completes the proof.
Exercises