Bourbaki

Exercise 13, § 1

Integration, VII, p. 79

Bourbaki marks this one as harder than the rest.

Let GG be a locally compact group operating continuously on the left in a locally compact Polish space TT, β\beta a left Haar measure on GG, and ν\nu a positive measure on TT quasi-invariant under GG. a) There exists a function (s,x)↦χ(s,x)>0(s, x) \mapsto \chi(s, x) > 0 on G×TG \times T, locally (β⊗ν)(\beta \otimes \nu)-integrable, such that for every s∈Gs \in G, the function x↦χ(s−1,x)x \mapsto \chi(s^{-1}, x) is locally ν\nu-integrable and satisfies γ(s)ν=χ(s−1,⋅)⋅ν\gamma(s)\nu = \chi(s^{-1}, \cdot) \cdot \nu. (Show that (s,x)↦(s,sx)(s, x) \mapsto (s, sx) transforms β⊗ν\beta \otimes \nu into an equivalent measure, by making use of criterion 3) of Th. 2 of Ch. V, §5, No. 5; let χ(s−1,x)dβ(s) dν(x)\chi(s^{-1}, x)d\beta(s)\, d\nu(x) be this equivalent measure. For φ∈H(G)\varphi \in \mathscr{H}(G) and ψ∈H(T)\psi \in \mathscr{H}(T),

∫φ(s) dβ(s)∫ψ(sx) dν(x)=∫φ(s) dβ(s)∫ψ(x)χ(s−1,x) dν(x), \int \varphi(s)\, d\beta(s) \int \psi(sx)\, d\nu(x) = \int \varphi(s)\, d\beta(s) \int \psi(x)\chi(s^{-1}, x)\, d\nu(x),

whence ∫ψ(sx) dν(x)=∫ψ(x)χ(s−1,x) dν(x)\int \psi(sx)\, d\nu(x) = \int \psi(x)\chi(s^{-1}, x)\, d\nu(x) except on a locally β\beta-negligible set N(ψ)N(\psi). Next make use of Lemma 1 of Ch. VI, §3, No. 1; then modify χ\chi on a (β⊗ν)(\beta \otimes \nu)-negligible set.)

b) Show that for any s,ts, t in GG, one has

χ(st,x)=χ(s,tx)χ(t,x) \chi(st, x) = \chi(s, tx)\chi(t, x)

except on a ν\nu-negligible set of values of xx (make use of the relation γ(st)ν=γ(s)(γ(t)ν)\gamma(st)\nu = \gamma(s)(\gamma(t)\nu)).

c) Show that the function χ\chi of a) is determined up to a locally (β⊗ν)(\beta \otimes \nu)-negligible subset of G×TG \times T.

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.