Bourbaki

Exercise 3, § 1

Integration, VII

Let G be a locally compact group, μ\mu a left Haar measure on G, and ν=ΔG−1/2⋅μ\nu = \Delta_G^{-1/2} \cdot \mu. Show that

γ(s)ν=ΔG(s)1/2ν,δ(s)ν=ΔG(s)1/2ν,ν˙=ν. \gamma(s)\nu = \Delta_G(s)^{1/2}\nu, \quad \delta(s)\nu = \Delta_G(s)^{1/2}\nu, \quad \dot{\nu} = \nu.
Solution

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Transcribed from the printed volume. Not translated.