Bourbaki

Exercise 12, § 4

Lie Groups and Lie Algebras, III, 381

Let GG be a finite-dimensional connected real or complex Lie group and α\alpha a left invariant differential form of degree pp on GG. For α\alpha to be right invariant too, it is necessary and sufficient that dα=0d\alpha = 0. (Observe that the condition for right invariance can be written

∧p(tAd(s)).α(e)=α(e) \wedge^p(t\mathrm{Ad}(s)) . \alpha(e) = \alpha(e)

for all s∈Gs \in G and hence it is equivalent to the condition

∑j=1f⟨α(e),u1∧⋯∧uj−1∧[u,uj]∧uj+1∧⋯∧up⟩=0 \sum_{j=1}^f \langle \alpha(e), u_1 \wedge \cdots \wedge u_{j-1} \wedge [u, u_j] \wedge u_{j+1} \wedge \cdots \wedge u_p \rangle = 0

for all u,u1,…,upu, u_1, \ldots, u_p in L(G)L(G).) In particular, the left and right invariant differential forms of degree 1 on GG form a vector space of dimension

dim⁡L(G)−dim⁡[L(G),L(G)]. \dim L(G) - \dim[L(G), L(G)].
Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.