Bourbaki marks this one as harder than the rest.
(a) Let Γ be a compact subgroup of G=GL(n,Qp). Show that there exists a conjugate of Γ which is contained in GL(n,Zp). (If T is a lattice of Qpn with respect to Zp (Commutative Algebra, Chapter VII, § 4, Definition 1), show that the stabilizer of T in Γ is open in Γ and hence of finite index and ∑γ∈ΓγT is a lattice which is stable under Γ.)
(b) Deduce that Gf is the union of the conjugates of GL(n,Zp).
(c) Deduce that every finite subgroup Φ of GL(n,Qp) has order a divisor of an(p), where an(p) is defined by
an(p)=(pn−1)(pn−p)…(pn−pn−1)if p=2an(p)=2n2(2n−1)(2n−2)…(2n−2n−1)if p=2. (Using (a), it can be assumed that
Φ⊂GL(n,Zp). Then use Exercise 4.)
(d) Show that every finite subgroup of SL(n,Qp) has order a divisor of sn(p), where sn(p)=p−1an(p) for p=2 and sn(2)=2an(2).