Bourbaki

Exercise 7, § 7

Lie Groups and Lie Algebras, III, 393

Bourbaki marks this one as harder than the rest.

In this exercise, let v2(a)v_2(a) denote the 2-adic valuation of an integer aa.

(a) Let Γ\Gamma be a finite subgroup of GL(n,Q)\mathbf{GL}(n, \mathbf{Q}). Show that there exists a positive definite quadratic form with coefficients in Z\mathbf{Z}, which is invariant under Γ\Gamma. Deduce (by the same argument as in Exercises 4 and 5) that, for all sufficiently large pp, Γ\Gamma is isomorphic to a subgroup of an orthogonal group O(n)\mathbf{O}(n) over the field Fp\mathbf{F}_p (resp. a subgroup of SO(n)\mathbf{SO}(n) if Γ\Gamma is contained in SL(n,Q)\mathbf{SL}(n, \mathbf{Q})).

(b) Suppose that Γ\Gamma is contained in SL(n,Q)\mathbf{SL}(n, \mathbf{Q}) and let 2e2^e denote the greatest power of 2 dividing the order of Γ\Gamma. Show that, if nn is odd, 2e2^e divides all the integers

bn(p)=(pn−1−1)(pn−3−1)…(p2−1) b_n(p) = (p^{n-1} - 1)(p^{n-3} - 1) \ldots (p^2 - 1)
for sufficiently large prime pp. (Use (a) and Exercise 13 of Algebra, Chapter IX, § 6.)

Show that, if nn is even and pp is a sufficiently large prime, 2e2^e divides the l.c.m. bn(p)b_n(p) of the integers

(pn−1)(pn−2−1)…(p2−1)/(pn/2+1) (p^n - 1)(p^{n-2} - 1) \ldots (p^2 - 1)/(p^{n/2} + 1)
(pn−1)(pn−2−1)…(p2−1)/(pn/2−1). (p^n - 1)(p^{n-2} - 1) \ldots (p^2 - 1)/(p^{n/2} - 1).
(Same method as for nn odd.) (c) Under the hypotheses of (b), we write
r(2,n)=n+[n2]+[n4]+⋯=n+v2(n!). r(2, n) = n + \left[ \frac{n}{2} \right] + \left[ \frac{n}{4} \right] + \cdots = n + v_2(n!).
Let AA be an integer ⩾3\geqslant 3. Show that 2r(2,n)−12^{r(2, n)-1} is the greatest power of 2 which divides all the bn(p)b_n(p) for p⩾Ap \geqslant A. (Same method† as in Exercise 6; use the existence of a prime number p⩾Ap \geqslant A such that p≡5(mod8)p \equiv 5 \pmod{8}.) Deduce the inequality e⩽r(2,n)−1e \leqslant r(2, n) - 1. (d) Conversely, let CnC_n be the subgroup of GL(n,Z)\mathbf{GL}(n, \mathbf{Z}) generated by the permutation matrices and the diagonal matrices with coefficients ±1\pm 1. The order of CnC_n is 2nn!2^{nn!} and v2(2nn!)=r(2,n)v_2(2^{nn!}) = r(2, n). If Γ2,n\Gamma_{2, n} denotes the intersection of a Sylow 2-group of CnC_n with SL(n,Z)\mathbf{SL}(n, \mathbf{Z}), deduce that the order of Γ2,n\Gamma_{2, n} is 2r(2,n)−12^{r(2, n)-1}.

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.