Bourbaki marks this one as harder than the rest.
In this exercise, let v2(a) denote the 2-adic valuation of an integer a.
(a) Let Γ be a finite subgroup of GL(n,Q). Show that there exists a positive definite quadratic form with coefficients in Z, which is invariant under Γ. Deduce (by the same argument as in Exercises 4 and 5) that, for all sufficiently large p, Γ is isomorphic to a subgroup of an orthogonal group O(n) over the field Fp (resp. a subgroup of SO(n) if Γ is contained in SL(n,Q)).
(b) Suppose that Γ is contained in SL(n,Q) and let 2e denote the greatest power of 2 dividing the order of Γ. Show that, if n is odd, 2e divides all the integers
bn(p)=(pn−1−1)(pn−3−1)…(p2−1) for sufficiently large prime
p. (Use (a) and Exercise 13 of
Algebra, Chapter IX, § 6.)
Show that, if n is even and p is a sufficiently large prime, 2e divides the l.c.m. bn(p) of the integers
(pn−1)(pn−2−1)…(p2−1)/(pn/2+1) (pn−1)(pn−2−1)…(p2−1)/(pn/2−1). (Same method as for
n odd.) (c) Under the hypotheses of (b), we write
r(2,n)=n+[2n]+[4n]+⋯=n+v2(n!). Let
A be an integer
⩾3. Show that
2r(2,n)−1 is the greatest power of 2 which divides all the
bn(p) for
p⩾A. (Same method† as in Exercise 6; use the existence of a prime number
p⩾A such that
p≡5(mod8).) Deduce the inequality
e⩽r(2,n)−1. (d) Conversely, let
Cn be the subgroup of
GL(n,Z) generated by the permutation matrices and the diagonal matrices with coefficients
±1. The order of
Cn is
2nn! and
v2(2nn!)=r(2,n). If
Γ2,n denotes the intersection of a Sylow 2-group of
Cn with
SL(n,Z), deduce that the order of
Γ2,n is
2r(2,n)−1.