Exercise 6, § 8
Lie Groups and Lie Algebras, III, 396
Let be a group of class (§ 5, Exercise 1) with . There exists on one and only one real Lie group structure such that the underlying manifold structure of class of is the given structure. (The uniqueness of follows from Corollary 1 to Theorem 1. Let be the normable Lie algebra associated with in Exercise 2 of § 5. There exist a real Lie group germ and an isomorphism of onto (§ 4, Theorem 3). Verify as in § 4, no. 1 that there exist a symmetric open neighbourhood of in and a mapping of class of into such that and for in . By shrinking , it can be assumed that is open in and that is an isomorphism of class of the manifold onto the manifold . There therefore exists on a real Lie group germ structure such that the underlying manifold structure of class is the given structure. For all , Int defines as analytic mapping of onto (Theorem 1). By Proposition 18 of § 1, there exists on a real Lie group structure inducing the same analytic structure as on an open neighbourhood of . By translation, the underlying manifold structure of class of on is the given structure.)
Solution
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